Q135. What is the equation of the circle passing through (1, 0) and (0, 1) and having the smallest possible radius?Mathematics — Conic Sections — Question 135 of 272A. x2 + y2 - 2x - y = 0B. x2 + y2 - x + 2y = 0C. x2 + y2 - x - y = 0D. x2 + y2 + x - y = 0Practice more Mathematics MCQs for entrance exam preparation on Examora.io.← Previous Question Next Question →