Q86. What is the equation of the hyperbola with vertices at (±3, 0) and a semi-latus rectum of 4?Mathematics — Conic Sections — Question 86 of 272A. 4x2 - 3y2 + 36 = 0B. 4x2 - 3y2 + 12 = 0C. 4x2 - 3y2 - 36 = 0D. None of thesePractice more Mathematics MCQs for entrance exam preparation on Examora.io.← Previous Question Next Question →