Q23. A particle carrying charge of 2e falls through a potential difference of 3.0 V. Calculate energy acquired by it. Physics — Electrostatics — Question 23 of 361A. 9.6 × 10-19 JB. 12.1 × 10-19 JC. 14.5 × 10-19 JD. 16.7 × 10-19 JE. 18.5 × 10-19 JPractice more Physics MCQs for entrance exam preparation on Examora.io.← Previous Question Next Question →